CA 05 - Reverse the array

Problem Statement: Reverse an array . Reversing an array means the elements such that the element becomes the , the element becomes and so on. arr[] = [1, 4, 3, 2, 6, 5] [5, 6, 2, 3, 4, 1] The first element moves to last position, the second element moves to second-last and so on. arr[] = [4, 5, 1, 2] [2, 1, 5, 4] The first element moves to last position, the second element moves to second last and so on. Solution: A brute force method to reverse the given array would be to create a new empty array and append each value from the original array one by one in reverse order using for loop. Example: arr= [4, 5, 1, 2] n=len(arr) rev_arr=[] for i in range (n-1,-1,-1): rev_arr.append(arr[i]) print(rev_arr) My approach: My preferred method of solving this problem would be to use the slicing concept. Slicing has the following syntax: array[start: end: step]. Using this we can solve the problem as follows: arr= [4, 5, 1, 2] print(arr[::-1]) By using -1 in the step part, we get the array values i